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-14x^2+x+42=0
a = -14; b = 1; c = +42;
Δ = b2-4ac
Δ = 12-4·(-14)·42
Δ = 2353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2353}}{2*-14}=\frac{-1-\sqrt{2353}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2353}}{2*-14}=\frac{-1+\sqrt{2353}}{-28} $
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